1800 rev/min * 2 pi rad/rev * 1 min/60 s = Omegai
1200 similarly ---> Omegaf
d omega = (Omegaf-omegai)
dt = 25 s
so
d Omega/dt = alpha = d omega/dt
average angular velocity
= (Omagaf+Omegai)/2
total radians = average vel * 25 sec
total revs = total radians/2pi
If a wheel revolving at 1800 r.p.m. slows down uniformly to 1200 r.p.m. in 25s, calculate the angular acceleration of the wheel and the number of revolutions it makes in this time.
1 answer