Asked by Chris
If a stake is placed in the ground and is 20cm. high and casts a shadow 12.5 cm. long, what time is it? (The sun rises at 6 a.m. and is overhead at noon.)
Answers
Answered by
Reiny
Major assumption ....
You must be at the equator , or between the two Cancers.
tanØ = 20/12.5 = 1.6
Ø = 57.99 or 58°
The assumption is that the time from 6:00 am to noon, or 6 hours , is proportional to the angle of the sun from 0° to 90°
t/6 = 58/90
t = 6(58/90) = 3.8666..
= 3 hrs and 52 minutes
the time is 9:52 am
You must be at the equator , or between the two Cancers.
tanØ = 20/12.5 = 1.6
Ø = 57.99 or 58°
The assumption is that the time from 6:00 am to noon, or 6 hours , is proportional to the angle of the sun from 0° to 90°
t/6 = 58/90
t = 6(58/90) = 3.8666..
= 3 hrs and 52 minutes
the time is 9:52 am
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.