If a salmon swims straight upward in the water fast enough to break through the surface at a speed of 5 meters per second, how high can it jump above water?

Answer 1

Vi = 5 m/s
a = g = -9.81 m/s^2

v = Vi - 9.81 t
v = 0 at top
so
0 = 5 - 9.81 t
t = .51 seconds to top
h = Hi + Vi t + (1/2)a t^2
h = 0 + 5(.51) - 4.9 (.51)^2
h = 2.55 - 1.27
h = 1.28 meters

Answer 2

by the way I could have done that really quickly by saying that the average speed up was half the starting speed.
h = (1/2)(5)(.51) = 1.28