If a reaction has a change of H of -120.0 kcals/mole and is spontaneous for all temperatures less than 200.0K, what is its ΔS?

1 answer

dG = dH - TdS
Set dG = 0, T is 200 and dH is -120.
Solve for dS
Then check it to see that temperatures below 200 have dG = negative and temperatures above 200 K have dG = positive.
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