If a dice is rolled 3 times, what is the probability of rolling a prime number, then a 2, and then a 5?

Answer 1

Probability of individual rolls:
1. Prime: 2,3 or 5 out of 6 faces => P(prime)=3/6=1/2
2. "2" out of 6 faces, P(2) = ?
3. "5" out of 6 faces. P(5) = ?

We can reasonably assume that the three rolls are independent of each other. The required probability is therefore the product of the probability of the individual rolls.