V1^2 / V2^2 = (40)^2 / (25)^2 = 2.56.
Therefore, the stopping distance at 40
mph is 2.56 times the stopping distance
at 25mph.
If a car is speeding down a road at 40 (mph), how long is the stopping distance compared to the stopping distance if the driver were going at the posted speed limit of 25 ?
Express your answer as a multiple of the stopping distance at 25
2 answers
how far would the car travel after slamming on the breales if it was initially moving at 75 mph?
2 answers