dv/dt = a which is constant
so
v = c + at
c is v when t = 0, v0
so
v = v0 + a t
dx/dt = v = v0 + a t
so
x = constant + v0 t + (1/2)at^2
constant is x when t = 0 or s0
x = s0 + v0 t + (1/2)at^2
(but we cheated and took physics so knew that)
If a car is driving in a straight line with constant acceleration a, initial velocity v0, and initial position s0, find a formula for the position function of the car.
How would I solve this equation?
1 answer