Asked by anshuman kumar
10. A car is moving in a straight line starts from rest, accelerates uniformly at 12 m/s2 for the first 5s, then travels at uniform speed for the next 2s and finally decelerates uniformly at 4 m/s2 for the next 5s. Draw the acceleration-time graph, velocity-time graphs and determine the distance travelled by the car during given time period.
Answers
Answered by
Henry
d1 = 0.5a*t^2 = 0.5*12*5^2 = 150 m.
V1 = a*t = 12 * 5 = 60 m/s.
d2 = V*t = 60m/s * 2s = 120 m.
d3 = Vo*t + 0.5a*t^2
d3 = 60*5 - 0.5*4*5^2 = 250 m.
d = d1+d2+d3 = 150+120+250 = 520 m.
V1 = a*t = 12 * 5 = 60 m/s.
d2 = V*t = 60m/s * 2s = 120 m.
d3 = Vo*t + 0.5a*t^2
d3 = 60*5 - 0.5*4*5^2 = 250 m.
d = d1+d2+d3 = 150+120+250 = 520 m.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.