avg speed= distanc/time
time for V1:
time= 2/5)/V1
time for V2:
time= 3/5/V2
total time= 2/5V1 + 3/5V2
=(2V2+3V1)/5V1V2
avgspeed=5V1V2/(2V2+3V1)
If a car covers 2/5th of the total distance with V1 speed and 3/5th distance with V2, then average speed is?
2 answers
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2 answers