If a baseball player has a batting average of 0.420, what is the probability that the player will get at least 2 hits

Question

in the next four times at bat?

Answer 1

prob(hit) = .42
prob(no hit ) = 1 - .42 = .58

at least 2 hits out of 4 ---> exclude : no hits, 1 hit

prob(no hits)
= C(4,0)(.42)^0 (.58)^4
= .113165
prob(1hit)
= C(4,1)(.42)(.58)^3
= .32779

prob(at least 2 hits)
= 1 - (.113165 + .32779)
= appr .559

or

you could do prob(2hits) + prob(3hits) + prob(4hits)
I bet you will get .559

Answer 2

this is dumb