if a ball is thrown vertically into the air, leaving the ground at a height of 1.8m, with a speed of 9.7m s -1. When it rises and falls to the ground what will the balls speed be as it hits the ground? please help with an explanation as i am so stuck, my exam is in two days and i need help.

thanx
Becky

3 answers

I would do this with energy.

Final total energy=initial total energy

1/2 m vf^2+zeroPE=mg(hi)+1/2 mvi^2

Vf^2=2g*1+vi^2

you may have had this formula presented to you for memory as..
Vf^2=Vi^2+2ad

Thank you Bob Pursley :)

Penejoldo