max height when KE is all PE
So, 1/2 mv^2 = mgh
Where does that take you?
A ball is thrown vertically upward with a speed of 20 m/s from the ground. The ball moves without resistance. First, find the maximum height the ball reaches.
The ball falls to the ground. Assume that the ball loses 10% of its energy, after each fall to the ground. How high will the ball reach after the first fall to the ground? How far will the ball travel before coming to rest?
(Consider that is a plastic ball with negligible dimensions. Initially the ball only has kinetic energy 1/2 mv^2. At the highest points, the ball has only dynamic energy mgh, where m is the mass of the ball, g=10m/sec^2 the gravity constant and h the vertical height from the ground.)
2 answers
Actually, I got the maximum height, which is 20 m, or at least I think that I got it, but I haven't answer the two other questions.
1 answer