If a ball is thrown into the air with a velocity ofc 40ft/s,its height in feet after t seconds is given by y=40t-16t^2. Find the velocity when t =2. Could you please show the steps

Answer 1

Velocity is the derivative of y(t)

V = dy/dt = 40 - 32 t

Plug in t = 2 and calculate the velocity. It will be negative, meaning that the ball is on the way down at that tiome.