h(t) = 50 + 40t - 10t^2
The rest is easy.
.
.
.
Right?
On planet Calculi, acceleration due to gravity is -20 ft/sec^2. A ball is thrown upward with an initial velocity of 40ft/sec from an initial height of 50.
a) Write the equation for the height of the ball, s(t), at time t.
b) Find the velocity when the ball hits the ground.
c) Find the time when the ball hits its maximum height.
I know velocity is the derivative and acceleration is the second derivative, but I'm getting confused on notation and solving. Thanks.
1 answer
2 answers