You used 8.99 - 3.65 = 5.34 g O2 for 8.99 g of Sc
5.34 + 8.99 = 14.33 g total Sc2O3
5.34 / 14.33 = .373 or 37.3 %
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check
O3 = 3 * 16 = 48
Sc2 = 2 * 45 = 90
total molecular mass = 138
48/138 = .347 or 34.7 %
looks like the experiment was a little off :)
if 8.99g of scandium and 8.99g of oxygen react to give scandium oxide and a leftover of oxygen 3.65g. what percentage of scandium oxide is the oxygen
1 answer
1 answer