Asked by Priscilla

If 6.40 x 10^-19 joule of work is required to move a proton between two points A and B in an electric field, what is the potential difference between points A and B?

Given:
W = 6.40 x 10^-19
Answered by drwls
Energy difference (J) = V * Q
= (Potential difference, in Volts) x (Charge, in Coulombs)

Solve for the potentila difference
Answered by Priscilla
Okay, would the answer be 6.40 V? I found the potential difference by diving the work and the elementary charge and i got 4 x 10^-57. And multiply that by the elementary charge.
Answered by drwls
No. the answer is not V = 6.4 volts Have you used the correct charge of a proton? It does not look like it.
Answered by diana
The answer is 4.00V
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