If 6.00g of carbon is heated in air, the mass of the product obtained could either be 22.0g or 14.6g depending on the amount of air present. Using calculations with what law will this be in accordance?

Answer 1

Proust's law or the law of definite composition.

6 gram C is 1/2 mole, the remaining 16 gram is 1 mole O, yielding 1/2 mole of CO2.

6 gram C is 1/2 mole, the remaining 8.6 g represents CO. I suspect there is a typo error here, instead of 14.6 it should have been 14.0

Answer 2

Pls explain