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if 6.0g of carbon is heated in air, the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of...Asked by Ibrahim
if 6.0g of carbon is heated in air, the mass of the product obtained could either be 22.0g or 14.0g depending on the amount of air present , with what law will this be accordance ? (c=12 , o =16
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Answered by
DrBob222
Law of Multiple Proportions.
mols C = grams/atomic mass = 6/12 = 0.5
2C + O2 ==> 2CO
mols CO formed = 0.5 x (2 mols CO/2 mols C) = 0.5
grams C = 0.5 mols x molar mass CO = 0.5 x 28 = 14 g CO
OR
C + O2 ==> CO2
mols CO2 produced = 0.5 mols C x (1 mol CO2/1 mol C) = 0.5
grams CO2 = mols CO2 x molar mass CO2 = 0.5 x 44 = 22 g CO2
The Law of Multiple Proportions says that when two elements form more than one compound that the mass of one element that combines with a fixed amount of a seconc element the ratio is of small whole numbers. In this case, the amount of O that combines with a fixed amount of C (0.5 mol) the O will be in small whole numbers; i.e., 1 atom O to 2 atoms O. This law was proposed in 1804 by John Dalton.
mols C = grams/atomic mass = 6/12 = 0.5
2C + O2 ==> 2CO
mols CO formed = 0.5 x (2 mols CO/2 mols C) = 0.5
grams C = 0.5 mols x molar mass CO = 0.5 x 28 = 14 g CO
OR
C + O2 ==> CO2
mols CO2 produced = 0.5 mols C x (1 mol CO2/1 mol C) = 0.5
grams CO2 = mols CO2 x molar mass CO2 = 0.5 x 44 = 22 g CO2
The Law of Multiple Proportions says that when two elements form more than one compound that the mass of one element that combines with a fixed amount of a seconc element the ratio is of small whole numbers. In this case, the amount of O that combines with a fixed amount of C (0.5 mol) the O will be in small whole numbers; i.e., 1 atom O to 2 atoms O. This law was proposed in 1804 by John Dalton.
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