I assume you have the solubility of KClO3 in water.
solubility in 50 g H2O will the just 1/2 the solubility in 100 g H2O.
If 50 grams of water saturated with potassium chlorate at 23*C is slowly evaporated to dryness, how many grams of the dry salt will be recovered? I know that I should know this.. But it has 50 grams of water instead of 100. ): Please, someone tell me how to do this?
4 answers
who cares
Solubility=mass/molar *1000/volume
Dats d formula nd u will get, 50g is d volume
Dats d formula nd u will get, 50g is d volume
Dontcare