if 5.00g magnesium is combined with 10.0 g of chlorine, show by calculation which substance is the limiting reactant and calculate the theoretical yield of magnesium chloride for the reaction. Someone PLEASE HELP ME!!!!

Answer 1

Mg + Cl2 -> MgCl2
5.00 g Mg / 24 g/mol / 1 (from balanced equation) = 0.21

10.0 g Cl2 / 71 g/mol / 2 (from balanced equation) = 0.070

Smallest number is limiting reactant = Cl2

Yield = 10.0 g Cl2 / 71g/mol X 1 mol MgCl2/1 mol Cl2 X 95 g MgCl2/mol = 13.4 g

Answer 2

10 g Cl2 / 71 g/mol /1 (balanced equation) = 0.141

Still the limiting reactant\
MgCl2 is still 13.4

Sorry!

Answer 3

On what