If 44.8L of carbon dioxide were produced, how many liters of oxygen must have reacted with glucose?

Answer 1

C6H12O6 + 3O2 ——-> 6CO2 + 6H2O

2 mols of CO2 for every mol of O2
since 22.4 liters per mol at STP for O2 and also for CO2
then 11.2 liters of O2

Answer 2

Whoops, sorry, not paying attention
44.8/2 = 22.4 liters CO2