if 4/3, m, 1, n...form a GP, the product of m and n is
8 answers
the term between them
sorry...forgot the square
the square of the term between them
the square of the term between them
Common ratio is 1/m which is equal to n/1 (i.e taken from any two close terms).
Thus: 1/m=n/1
Cross multiply
mn=1
Therefore the product of m and n is 1.
Thus: 1/m=n/1
Cross multiply
mn=1
Therefore the product of m and n is 1.
Thank you very well
T3=ar² ÷ m(T1)=ar
1=(4/3)r²
÷
m=(4/3)r
Therefore m=1/r
For n(T4),
T4= (3/4)×r³
÷
(T3)1= (3/4)r²
Therefore n/1=r
m=1/r
×
n=r
Therefore, m×n=1/r×r
MN=1
1=(4/3)r²
÷
m=(4/3)r
Therefore m=1/r
For n(T4),
T4= (3/4)×r³
÷
(T3)1= (3/4)r²
Therefore n/1=r
m=1/r
×
n=r
Therefore, m×n=1/r×r
MN=1
The answer is 1
Chiboy
mathematics
2 answers