if 4.1g of Cr is heateed with 9.3g of cl, what mass of crcl3 will be produce

Answer 1

Find the caps key on your keyboard and use it.
This is a limiting reagent (LR) problem.
Here is a procedure that will work all of your LR problems.
1. Write and balance the equatin.
Cr + 3Cl2 ==> 2CrCl3

2a. Convert grams Cr to mols. mols = grams/atomic mass = ?
2b. Do the same and convert grmas Cl2 to mols.

3a. Using the coefficients in the balanced equation, convert mols Cr to mols CrCl3.
3b. Do the same and convert mols Cl2 to mols CrCl3.
3c. It is likely that the values from 3a and 3b will not agree. In LR problems the correct value is ALWAYS the smaller one and the reagent responsible for that is called the LR.

4. Using the smaller value, convert mols to grams.
mols CrCl3 x molar mass CrCl3 = grams CrCl3.

Post your work if you get stuck.

Answer 2

i got 12.5g
am i right?

Answer 3

Right !. Good work. By the way, that equation I wrote is not balanced. It should be
2Cr + 3Cl2 ==>2CrCl3
Obviously you corrected that before you worked the problem.