If 32 g of kerosene of density 0.80 g/cm^3 are mixed with 8 g of water. What is the density of the resulting mixture

Answer 1

volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3

Answer 2

How did you got the 48

Answer 3

I don't know how he got 48

Answer 4

Please 🙏 solve this question

Answer 5

volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3

Answer 6

Is that the final answer

Answer 7

Answer

Answer 8

I don't really understand all this signs as it is written in this google so please make it easy for the audience GOD BLESS YOU

Answer 9

How did you get 48 as the answer