volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
If 32 g of kerosene of density 0.80 g/cm^3 are mixed with 8 g of water. What is the density of the resulting mixture
9 answers
How did you got the 48
I don't know how he got 48
Please 🙏 solve this question
volume = 8 cm^3 + 32 g / 0.8 g/ cm^3 = 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
mass = 32 + 8 = 40 g
40 g / 48 cm^3
Is that the final answer
Answer
I don't really understand all this signs as it is written in this google so please make it easy for the audience GOD BLESS YOU
How did you get 48 as the answer