If 3-x,6 and 3-5x are in gp.find the possible value of x
4 answers
I need the solution
to form a GP,
6/(3-x) = (3-5x)/6
(3-5x)(3-x) = 36
5x^2 - 18x + 9 = 36
5x^2 - 18x - 27 = 0
x = (18 ± √864)/10
= (18 ± 12√6)/10
= (9 ± 6√6)/5
6/(3-x) = (3-5x)/6
(3-5x)(3-x) = 36
5x^2 - 18x + 9 = 36
5x^2 - 18x - 27 = 0
x = (18 ± √864)/10
= (18 ± 12√6)/10
= (9 ± 6√6)/5
6 / (3 - x) = (3 - 5x) / 6
"cross" multiplying ... 36 = 9 - 18 x + 5 x^2
5 x^2 - 18 x - 27 = 0
use the quadratic formula to find values of x
"cross" multiplying ... 36 = 9 - 18 x + 5 x^2
5 x^2 - 18 x - 27 = 0
use the quadratic formula to find values of x
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3 answers