If 3 is subtracted from the numerator of a certain fraction, the value becomes 2/3. If 10 is added to the denominator of the original fraction, the value becomes 1/2. Find the original fraction.
Solve the problems by using 2 variables
HOW DO I START THIS WHAT ARE THE 2 EQUATIONS and can you label the variable like let variable x = 3x-1
2 answers
i mean label the variable like let x= # of somthing
original fraction is n/d
(n-3)/d = 2/3
n/(d+10) = 1/2
3(n-3) = 2d
2n = d+10
3n - 2d = 9
2n - d = 10
n = 11
d = 12
check:
(11-3)/12 = 8/12 = 2/3
11/(12+10) = 11/22 = 1/2
(n-3)/d = 2/3
n/(d+10) = 1/2
3(n-3) = 2d
2n = d+10
3n - 2d = 9
2n - d = 10
n = 11
d = 12
check:
(11-3)/12 = 8/12 = 2/3
11/(12+10) = 11/22 = 1/2
2 answers