S + O2 --> SO2
3.20 kg = 3200 grams. Convert to mols. mols = grams/molar mass.
Use the coefficients in the balanced equation to convert mols S to mols SO2
Now use PV = nRT, substitute mols for n, substitute the conditions in the problem (P and T) and solve for volume. Don't forget T must be in kelvin.
If 3.20 kg of Sulphur reacts with oxygen, calculate the volume in millileters of sulphur dioxide gas formed at 30.5 degrees Celsius and 1.04 atm.
1 answer
1 answer