91g = 2.84 moles of O2
add that to 2.84 moles of S
and that will be 2.84 moles of SO2. How many grams is that?
Determine the mass of sulphur(iv) oxide obtained when 91g of oxygen reacts completely with sulphur according to the following equation: S+O2 'n SO2 (S=32,O=16)
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