AgNO3 + KCl ==> AgCl + KNO3
mols KCl = grams/molar mass = about 0.01 mol but you need to do it more accurately.
Convert mol KCl to mol AgNO3. That's 0.01 mol also (look at the coefficients in the balanced equation).
Then M = mols/L. mol = 0.01; L = 0.026
M = 0.01/0.026 = ?
If 26.0mL of AgNO 3 is needed to precipitate all the Cl −ions in a 0.750-mg sample of KCl (forming AgCl), what is the molarity of the AgNO 3 solution
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