What mass of KCl \rm KCl is needed to precipitate the silver ions from 13.0mL mL of 0.200 M M AgNO 3 \rm AgNO_3 solution

Answer 1

AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

mols AgNO3 = M x L = ?
mols KCl = the same (Look at the coefficients in the balanced equation.)
g KCl = mols KCl x molar mass KCl.

Answer 2

8.34