Molality is defined as the number of moles of solute per kilogram of solvent.
First, we need to calculate the number of moles of glucose:
Number of moles = mass of glucose / molar mass of glucose
Number of moles = 21.3 g / 180 g/mol
Number of moles = 0.1183 mol
Next, we need to calculate the mass of water in kg:
Mass of water = volume of water x density of water
Mass of water = 5.00 mL x 1.00 g/mL = 5.00 g = 0.00500 kg
Now, we can calculate the molality:
Molality = number of moles of solute / mass of solvent in kg
Molality = 0.1183 mol / 0.00500 kg = 0.0237 m
Therefore, the molality of the solution is 0.0237 m. The correct answer is A. 0.0237 m.
If 21.3 g of glucose (CHO)(180g/mol) is dissolved in 5.00 1. of deionized water, what is the molality of the solution? (The density of water is 1.00 g/ml.) A.
A.0.0237 m
B.0.592 m
C. 0.118 m.
D. 4.26 m
E. 0.00426 m
1 answer