What is the percent by mass of glucose in a solution containing 0.15 moles of glucose dissolved in 410g acetic acid? The molar mass of glucose is 180g/mol

Answer 1

0.15 moles glucose = 0.15 x 180 = 27.00 grams.
mass percent = g solute/100 g soln.
[27.00 g glucose/(27.0+410.0)]*100 = ??

Answer 2

6.2%