If 2 numbers have a difference of 2.38, one number is 3 times bigger than the other number and the two numbers both add up to 6, what could the two numbers be?

Answer 1

y-x = 2.38
y = 3x
x+y = 6

You only need two of the equations to solve for x and y.

As it happens, there is no solution to all three conditions:

Using

y-x = 2.38
y = 3x

3x-x = 2.38
2x = 2.38
x = 1.19
y = 3x = 5.37
Fails to satisfy x+y=6

or, using

y-x = 2.38
x+y = 6

2x = 8.38
x = 4.19
y = 1.81
Fails to satisfy y=3x

or, using
y = 3x
x+y = 6

x+3x = 6
4x = 6
x = 1.5
y = 4.5
Fails to satisfy y-x = 2.38

Answer 2

THERE IS NO SOULITION!

Answer 3

THERE IS NO ANSWER!! IT'S IMPOSSIBLE

Answer 4

Ya yeet
:)

Answer 5

IT IS IMPOSSIBLE WE HAD THIS QUESTION AT SCHOOL AND NO ONE NOT EVEN THE TEACHERS COULD WORK IT OUT!

Answer 6

It is impossible you divs

Answer 7

Your an idiot

Answer 8

bar model
6 - 2.38 = 3.62
3.62 divide by 2 = 1.81

therefore 1.81 plus 4.19 (2.38 + 1.81)

Answer 9

If 2 numbers have a difference of 2.38, one number is 3 times bigger than the other number and the two numbers both add up to 6, what could the two numbers be?

If this is in oxf owl mastery - the Q is actually not this -
Q1 = 2 numbers have a difference of 2.38 and the two numbers add up to 6 (see above answer)
Q2 = 2 numbers have a difference of 2.38 but one of the numbers is 3 times bigger than the other (BUT doesn't say have to add to 6)