x+y = 32
4x-5 = 8y
Solve for x and y, then x-y
The sum of 2 numbers is 32.when 5 subtracted from 4 times 1 of the numbers,the result is 8 times the other number.find the difference between the 2 numbers.
5 answers
X+y=32
4x-5=8y
X=32-y
4(32-Y)=8y
128-4Y=8y
128=12y
Y=32/3
x+y=32
x+32/3=32
x=32-32/3
x=64/3, y=32/3
4x-5=8y
X=32-y
4(32-Y)=8y
128-4Y=8y
128=12y
Y=32/3
x+y=32
x+32/3=32
x=32-32/3
x=64/3, y=32/3
Nice one
Happy birthday and many more with
What are solving it is total rubbish
4x-5=8y
4x+8y=5
Jeez
4x-5=8y
4x+8y=5
Jeez