If 2.0gram of calcium carbonate were reacted with excess dilute hydrochloric acid. What volume of carbon dioxide would be given out at S.T.P
3 answers
Nothing
write the equation.
determine how many moles of CO2 you will get
each mole occupies 22.4 L at STP
determine how many moles of CO2 you will get
each mole occupies 22.4 L at STP
CaCO3(s) + 2HCl(aq)> CaCl2(aq) +CO2(g)+H2O(l)
RFM of CaCO3 =(2×40)+12+(3×16)
=80+12+48=140
No of moles of CaCO3 that reacted =2/140
=1/70 moles
mole ratio of CaCO3 to CO2 is 1:1
therefore, the no of moles of CO2 produced= 1/70 moles
Molar gas volume at STP =22.4L
1 mole=22.4L
1/70 moles=??
=1/70×22.4
=0.32L
RFM of CaCO3 =(2×40)+12+(3×16)
=80+12+48=140
No of moles of CaCO3 that reacted =2/140
=1/70 moles
mole ratio of CaCO3 to CO2 is 1:1
therefore, the no of moles of CO2 produced= 1/70 moles
Molar gas volume at STP =22.4L
1 mole=22.4L
1/70 moles=??
=1/70×22.4
=0.32L
3 answers