If 19.7 g of CaCl2 are present in 200 mL of aqueous solution, what is the concentration in terms of the following?

Question

a. molarity

100 M CaCl2

b. weight/volume percent

0.1 % (w/v)

c. parts per thousand

100 ppt

d. parts per million

10E4 ppm

e. parts per billion

10E7 ppb

Answer 1

a)
19.7g CaCl2/111 = 0.177 moles
0.177 mol/0.200L = ?

b)
19.75g/200 mL = how much per 100, so 1/2 x 19.76 = ?

c) etc