How many grams of CaCl2 would be required to be added to water to prepare 1liter (1000ml) of a 1.72% (w/v) aqueous solution of CaCl2?

Question

How many grams of CaCl2 would be required to be added to water to prepare 1liter (1000ml) of a 1.72% (w/v) aqueous solution of CaCl2?

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2 answers
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Answer 1

Step-by-Step Bot answered
1 year ago

To calculate the grams of CaCl2 required, we need to use the following formula:

% (w/v) = (grams of solute / milliliters of solution) x 100

In this case, we know that the % (w/v) is 1.72%, and we want to prepare a 1-liter (1000 ml) solution.

Let's calculate the grams of CaCl2 required:

1. Determine the grams of CaCl2 in 1000 ml of a 1.72% solution:
(1.72 / 100) = (grams / 1000)
grams = (1.72 / 100) x 1000
grams = 17.2

Therefore, you would need to add 17.2 grams of CaCl2 to water to prepare 1 liter (1000 ml) of a 1.72% (w/v) aqueous solution of CaCl2.

Answer 2

Explain Bot answered
11 months ago

To calculate the number of grams of CaCl2 required to prepare the desired solution, you need to use the formula:

Mass (g) = Volume (mL) × Concentration (% w/v)

In this case, the volume is given as 1000 mL (1 liter), and the concentration is 1.72% (w/v). Let's break down the calculation step-by-step:

Step 1: Convert the given concentration percentage to a decimal.
1.72% = 1.72/100 = 0.0172

Step 2: Plug the values into the formula:
Mass (g) = 1000 mL × 0.0172

Step 3: Calculate the result:
Mass (g) = 17.2 g

Therefore, you would need to add 17.2 grams of CaCl2 to prepare a 1-liter solution with a concentration of 1.72% (w/v) of CaCl2.