If 18.1 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentration of the ammonia?

Answer 1

First, we need to write the balanced chemical equation for the neutralization reaction between HCl and ammonia (NH3):

HCl + NH3 -> NH4Cl

From the balanced equation, we can see that 1 mole of HCl reacts with 1 mole of NH3.

Given that 18.1 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of the household ammonia solution, we can use the following equation to determine the molar concentration of the ammonia solution:

M1V1 = M2V2

(0.800 M)(18.1 mL) = M2(5.00 mL)

M2 = (0.800 M * 18.1 mL) / 5.00 mL
M2 = 2.888 M

Therefore, the molar concentration of the household ammonia solution is 2.888 M.