If 17.0 mL of 0.590 M CaCl2 are mixed with 46.6 mL of 0.480 M CaCl2, calculate the molarity of each ion in the final solution? Assume the volumes are additive.

Answer 1

moles soln 1 = M x L = ??
moles soln 2 = M x L = ??
M CaCl2 = total moles/total L.

M Ca^+2 = M CaCl2
M Cl^- = 2 x M CaCl2.