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if 16r of METHANOL are reacted wtih an excess of PBr3, how many grams of CH3Br would be formed if there is a 25% yield?

eqn; CH2OH + PBr3 --> CH3Br + H3PO3

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Balance that equation.

Then, how many moles of methanol is 16 grams.

Use the mole ratio to get the moles of CH3Br. Finally, multipy that by .25

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