Asked by Brittany
Methanol (CH4O) is converted to bromomethane (CH3Br) as follows:
CH4O + HBr --> CH3Br + H2O
If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percent yield?
CH4O + HBr --> CH3Br + H2O
If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percent yield?
Answers
Answered by
DrBob222
Here is a worked example of how to solve simple stoichiometry problems, including percent yield.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
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