If 150.0 mL of 1.00 M C6H12O6 are diluted to 750.0 mL, what is the molarity of the final solution?
____ M?
2 answers
mL1 x M1 = mL2 x M2
Use Dilution Equation (M1V1 = M2V2) to solve this problem.
M1=1.00mols/L
M2=?
V1=150.0mL, convert to Liter
V1=150mL*(1L/1000mL)=.15L
Do the same to V2
V2=750.0mL(1L/1000mL)=.75L
plug in the numbers into the Equation
M1V1=M2V2
M2=M1V1/V2, M2=(1mols/L)*(.15L)/(.75L)=.2M
The molarity of the final Solution is .2M.
M1=1.00mols/L
M2=?
V1=150.0mL, convert to Liter
V1=150mL*(1L/1000mL)=.15L
Do the same to V2
V2=750.0mL(1L/1000mL)=.75L
plug in the numbers into the Equation
M1V1=M2V2
M2=M1V1/V2, M2=(1mols/L)*(.15L)/(.75L)=.2M
The molarity of the final Solution is .2M.