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If 15.5 J of heat are removed from 14.6 g of mercury (specific heat = 0.142 J/g oC) at 25.0 oC, what is the final temperature of the mercury sample in oC?

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q = mass Hg x specific heat Hg x (Tfinal-Tinitial)
-15.5 J = 14.6 x 0.142 x (Tf-25.00)
Solve for Tf = Tfinal. Post your work if you get stuck.

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