If 125 cal of heat is applied at 60.0g piece of copper and 2.0 degrees celsius, what wiill the final temperature be? The specific heat copper is 0.0920 cal

Answer 1

q = mass Cu x specific heat Cu x (Tfinal-Tinitial)
125 cal = 60.0 g x 0.0920 cal/g*C x (Tfinal - 20)
Solve for Tfinal.