I'm not sure how to solve this:

If 125 cal of heat is applied to a 60.0-g piece of copper at 20.0∘C , what will the final temperature be? The specific heat of copper is 0.0920 cal/(g⋅∘C). Express the final temperature numerically in degrees Celsius

Thanks

15 answers

heatgained= mass*c*(Tf-Ti)

Tf= 125/(60*.0920) + 20

I'm sorry, I haven't really understood what you've done. could you maybe break it down for me? I'm new at this whole chem thing. What is Tf and Ti?
She's good, she's about to get her degree in education!

Thanks
-MC

Tf is the final temperature, Ti is the initial temperature.

I started from heat=mc deltaTemp
then solved for final temperature Tf

So what I'm getting as I set up the equation is 60g x 125 x 60
and that doesn't seem right

Hmmmm. that is far from right.

Heatgained= mass*specificheat*change in temp

change in temp= heatgaind/(specificheat*mass)

change in temp= 125cal/(.0920cal/gC * 60g) = 33.6 check that

chaknge in temp= finaltemp-initial temp

so final temp= 33.6+20 C

53.6 c

47.6

47.6 *C is correct.

none of those are correct

42.6

43 try rounding it

45.6 ∘C

44.6 °C

all wrong lmfaoo