To determine the amount of Calcium Carbonate (CaCO₃) produced from the reaction of Calcium Oxide (CaO) and Carbon Dioxide (CO₂), we can start by looking at the balanced chemical equation for the reaction:
\[ \text{CaO} + \text{CO}_2 \rightarrow \text{CaCO}_3 \]
In this reaction, one mole of calcium oxide reacts with one mole of carbon dioxide to produce one mole of calcium carbonate. Therefore, the mass of calcium carbonate produced will be the sum of the masses of the two reactants.
Given the masses:
- Mass of Calcium Oxide (CaO) = 120g
- Mass of Carbon Dioxide (CO₂) = 90g
The total mass of the products will be the sum of the masses of the reactants:
\[ 120 \text{g (CaO)} + 90 \text{g (CO₂)} = 210 \text{g (CaCO}_3\text{)} \]
Thus, the correct estimate of the amount of Calcium Carbonate produced is 210g.
Therefore, the answer is: 210g (sum of 120g and 90g).
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