I2 + Cl2 ==> 2ICl (Is that the equation?)
initially:
(I2) = 0.5/2.0 = ??
(Cl2) = 0.5/2.0 = ??
(ICl)= 0
change:
(ICl) = +2x
(I2) = -x
(Cl2) = -x
equilibrium:
(ICl) = 0 + 2x = 2x
(I2) = (0.5/2.0) - x = 0.25 - x
(Cl2) = (0.5/2.0) - x = 0.25 - x
Set up Keq, substitute, and solve for x. Post your work if you get stuck. Check my work.
If 0.50 mol of iodine and 0.50 mols of chlorine are initially placed into a 2.00-L reaction vessel at 25 Degrees Celsius, find the concentrations of all entities at equilibrium.
2 answers
Keq = [0.25 - x] / [0.25 - x][2x]
= [0.25 - ] / [0.25 - ][2()]
=
What numbers need to be substituted?
= [0.25 - ] / [0.25 - ][2()]
=
What numbers need to be substituted?