the sum of heats gained is zero.
heatgainedicemelting+ heatgained by water heating+ heat gained alumin heating=0
.045*Hfice+(.045)specheatwater*(Tf-0)+.390*specheatwater*(Tf-34)+.150specheatAl(Tf-34)=0
solve for Tf
If 0.045 kg of ice at 0 C is added to 0.390 kg of water at 34 C in a 0.150 kg aluminum calorimeter cup, what is the final temperature of the water?
Please help!
3 answers
is Hfice heat fushion of ice? or is latent heat the same as heat fushion?
so i did
(0.45*333.55) + (0.045*4.816)(T-0) + (0.39*4.186)(T-34) + (.15*920)(T-34) = 0
15.009 + 0.18837T + 55.51-1.63254T + 4692 - 138T = 0
4762.519 - 139.4T = 0
T = 34.16 C
But I'm getting the wrong answer. Am I using the wrong number for Al? Or Hf?
(0.45*333.55) + (0.045*4.816)(T-0) + (0.39*4.186)(T-34) + (.15*920)(T-34) = 0
15.009 + 0.18837T + 55.51-1.63254T + 4692 - 138T = 0
4762.519 - 139.4T = 0
T = 34.16 C
But I'm getting the wrong answer. Am I using the wrong number for Al? Or Hf?
4 answers