Question

If 0.045 kg of ice at 0 C is added to 0.390 kg of water at 34 C in a 0.150 kg aluminum calorimeter cup, what is the final temperature of the water?

Please help!

Answer 1

the sum of heats gained is zero.

heatgainedicemelting+ heatgained by water heating+ heat gained alumin heating=0

.045*Hfice+(.045)specheatwater*(Tf-0)+.390*specheatwater*(Tf-34)+.150specheatAl(Tf-34)=0
solve for Tf

Answer 2

is Hfice heat fushion of ice? or is latent heat the same as heat fushion?

Answer 3

so i did

(0.45*333.55) + (0.045*4.816)(T-0) + (0.39*4.186)(T-34) + (.15*920)(T-34) = 0

15.009 + 0.18837T + 55.51-1.63254T + 4692 - 138T = 0

4762.519 - 139.4T = 0

T = 34.16 C

But I'm getting the wrong answer. Am I using the wrong number for Al? Or Hf?