Identify the conic section whose equation is given:

x2 + 10x + y2 + 12y = 60

1 answer

x^2 + 10 x + (10/2)^2 + y^2 +12 y + (12/2)^2 = 60 +(10/2)^2 + (12/2)^2

x^2 + 10 x + 25 + y^2 + 12 y + 36 = 60 + 25 + 36

(x+5)^2 + (y+6)^2 = 121

That is a circle with radius 11 centered at (-5,-6).