consider y = 9^x
and look at its graph
http://www.wolframalpha.com/input/?i=plot+y+%3D+9%5Ex
You might want to change the equation to y = 2^x in the input window of Wolfram to show the shape is basically the same for any positive base > 1.
if x = 0 , 9^x = 1
if x is positive, 9^x > 1
if x is negative 9^x < 1
There is no value of x which makes 9^x = 0
nor can 9^x ever be < 0
identify the conditions on x that make the following statement true, if they can be made true at all:
9^x > 1
9^x < 1
9^x = 1
9^x = 0
9^x < 0
what is the question asking for?
3 answers
Do i need to replace x to a number? or the question just asking to explain how x can become that equation like your answer ?
if x = 0 , 9^x = 1
if x is positive, 9^x > 1
if x is negative 9^x < 1
There is no value of x which makes 9^x = 0
nor can 9^x ever be < 0
if x = 0 , 9^x = 1
if x is positive, 9^x > 1
if x is negative 9^x < 1
There is no value of x which makes 9^x = 0
nor can 9^x ever be < 0
what I stated is true for any positive base > 1
thus it is true for 9^x
thus it is true for 9^x
1 answer